Re: [android-developers] Basic String Array question :(

On Fri, Dec 24, 2010 at 8:12 PM, Mystique <joven.chiew@gmail.com> wrote:

String[] lv_arr;

for(int i=1; i<11; i++){
               lv_arr[i] = "hello";
         }

When I toast the value of lv_arr[i] it is null.

If this is your actual code, you need to initialize the array.

String[] lv_arr = new String[11];

Second, array indexing is zero-based, so you would start your loop from 0 and go to 9 (where i  < 10).

 

If I do this:

String[] lv_arr = {"hello", hello", "hello"} + the for loop, I can get the hello value when I do the toast. but [3]-[10] is still null value.

You've initialized an array to exactly three elements. Anything after that (index 3 and above) is non-existent. 

These are really basic Java concepts. If you don't understand this, I highly recommend you go study Java on it's own and figure this stuff out before trying to do an Android project. You're going to run into a lot of headaches if you try to learn both at the same time.

-------------------------------------------------------------------------------------------------
TreKing - Chicago transit tracking app for Android-powered devices

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